An oxidation-reduction reaction in which
3 electrons are transferred has a $\Delta$Gº of 17.37 kJ mol–1 at
25 oC. The value of Eo
cell (in V) is ______ × 10–2.
(1 F = 96,500 C mol–1)
Answer (integer)
-6
Solution
$\Delta$Gº = 17.37 kJ ; n = 3
<br><br>$\Delta$Gº = -nF$E_{cell}^o$
<br><br>$\Rightarrow$ $E_{cell}^o$ = $- {{17.37 \times 1000} \over {3 \times 96500}}$
<br><br>= -0.06 = -6.00 $\times$ 10<sup>-2</sup>
About this question
Subject: Chemistry · Chapter: Electrochemistry · Topic: Electrochemical Cells
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