The correct order of reduction potentials of the following pairs is
A. Cl2/Cl$-$
B. I2/I$-$
C. Ag+/Ag
D. Na+/Na
E. Li+/Li
Choose the correct answer from the options given below.
Solution
$\mathrm{E}_{\mathrm{C}_{2} / \mathrm{CI}}^{\circ}=+1.36 \mathrm{~V}$<br/><br/>
$\mathrm{E}_{\mathrm{I}_{2} / \mathrm{I}^{-}}^{0}=+0.54 \mathrm{~V}$<br/><br/>
$\mathrm{E}_{\mathrm{Ag}^{+} / \mathrm{Ag}}^{\circ}=+0.80 \mathrm{~V}$<br/><br/>
$\mathrm{E}_{\mathrm{Na}^{+} / \mathrm{Na}}^{\circ}=-2.71 \mathrm{~V}$<br/><br/>
$\mathrm{E}_{\mathrm{L}^{+} / \mathrm{Li}}=-3.05 \mathrm{~V}$
About this question
Subject: Chemistry · Chapter: Electrochemistry · Topic: Electrochemical Cells
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