The resistance of a conductivity cell with cell constant 1.14 cm$-$1, containing 0.001 M KCl at 298 K is 1500 $\Omega$. The molar conductivity of 0.001 M KCl solution at 298 K in S cm2 mol$-$1 is ____________. (Integer answer)
Answer (integer)
760
Solution
$$K = {1 \over R} \times {l \over A} = \left( {\left( {{1 \over {1500}}} \right) \times 1.14} \right)$$ S cm<sup>$-$1</sup><br><br>$$ \Rightarrow { \wedge _m} = 1000 \times {{\left( {{{1.14} \over {1500}}} \right)} \over {0.001}}$$ S cm<sup>2</sup> mol<sup>$-$1</sup><br><br>= 760 S cm<sup>2</sup> mol<sup>$-$1</sup><br><br>$\Rightarrow$ 760
About this question
Subject: Chemistry · Chapter: Electrochemistry · Topic: Electrochemical Cells
This question is part of PrepWiser's free JEE Main question bank. 127 more solved questions on Electrochemistry are available — start with the harder ones if your accuracy is >70%.