The quantity of electricity in Faraday needed to reduce 1 mol of Cr2O$_7^{2 - }$ to Cr3+ is ____________.
Answer (integer)
6
Solution
$\overset{+6}{\mathrm{Cr}_2} \mathrm{O}_7^{2-} \longrightarrow 2 \mathrm{Cr}^{3+}$<br/><br/>
$\because$ Each $\mathrm{Cr}$ is converting from $+6$ to $+3$<br/><br/>
$\therefore 6$ faradays of charge is required
About this question
Subject: Chemistry · Chapter: Electrochemistry · Topic: Electrochemical Cells
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