Medium MCQ +4 / -1 PYQ · JEE Mains 2022

Which of the following will have maximum stabilization due to crystal field?

  1. A [Ti(H<sub>2</sub>O)<sub>6</sub>]<sup>3+</sup>
  2. B [Co(H<sub>2</sub>O)<sub>6</sub>]<sup>2+</sup>
  3. C [Co(CN)<sub>6</sub>]<sup>3$-$</sup> Correct answer
  4. D [Cu(NH<sub>3</sub>)<sub>4</sub>]<sup>2+</sup>

Solution

The given complexes are: <br/><br/> $\left[\mathrm{Ti}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+},\left[\mathrm{Co}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+},\left[\mathrm{Co}(\mathrm{CN})_{6}\right]^{-3},\left[\mathrm{Cu}\left(\mathrm{NH}_{3}\right)_{4}\right]^{2+}$ <br/><br/> $\mathrm{CN}^{-}$is the strongest ligand among the given complexes CFSE value for the $\left[\mathrm{Co}(\mathrm{CN})_{6}\right]^{-3}$ complex will be highest as it has $d^{6}$ configuration with a CFSE value of $-2.40 \,\Delta_{0}+2 \mathrm{P}$, where $P$ represents pairing energy and $\Delta_{0}$ represents splitting energy in octahedral field. <br/><br/> The value of $\Delta_{0}$ is high for cyanide complexes.

About this question

Subject: Chemistry · Chapter: Coordination Compounds · Topic: Ligands and Coordination Number

This question is part of PrepWiser's free JEE Main question bank. 173 more solved questions on Coordination Compounds are available — start with the harder ones if your accuracy is >70%.

Drill 25 more like these. Every day. Free.

PrepWiser turns these solved questions into a daily practice loop. Chapter-wise drills, full mocks, AI doubt chat. No auto-renew.

Start free →