Match List I with List II
| LIST I (Compound) |
LIST II (Colour] |
||
|---|---|---|---|
| A. | $\mathrm{Fe}_4\left[\mathrm{Fe}(\mathrm{CN})_6\right]_3 \cdot \mathrm{xH_2O}$ | I. | Violet |
| B. | $\left[\mathrm{Fe}(\mathrm{CN})_5 \mathrm{NOS}\right]^{4-}$ | II. | Blood Red |
| C. | $[\mathrm{Fe}(\mathrm{SCN})]^{2+}$ | III. | Prussian Blue |
| D. | $\left(\mathrm{NH}_4\right)_3 \mathrm{PO}_4\cdot12 \mathrm{MoO}_3$ | IV. | Yellow |
Choose the correct answer from the options given below:
Solution
<p>To match List I with List II correctly, we need to identify the colors associated with each compound.</p>
<p>Let's analyze each compound:</p>
<p><b>1. </b> $\mathrm{Fe}_4\left[\mathrm{Fe}(\mathrm{CN})_6\right]_3 \cdot \mathrm{xH_2O}$ - This is known as Prussian Blue.</p>
<p><b>2. </b> $\left[\mathrm{Fe}(\mathrm{CN})_5 \mathrm{NOS}\right]^{4-}$ - This complex is known to have a violet color.</p>
<p><b>3. </b> $[\mathrm{Fe}(\mathrm{SCN})]^{2+}$ - This ion is known for its blood red color.</p>
<p><b>4. </b> $\left(\mathrm{NH}_4\right)_3 \mathrm{PO}_4\cdot12 \mathrm{MoO}_3$ - This is commonly known as Ammonium phosphomolybdate, which is yellow.</p>
<p>Matching each item, we get:</p>
<table class="tg" style="undefined;table-layout: fixed; width: 776px">
<colgroup>
<col style="width: 75px">
<col style="width: 252px">
<col style="width: 75px">
<col style="width: 374px">
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<thead>
<tr>
<th class="tg-7btt"></th>
<th class="tg-7btt">LIST I<br>(Compound)</th>
<th class="tg-7btt"></th>
<th class="tg-7btt">LIST II<br>(Colour)</th>
</tr>
</thead>
<tbody>
<tr>
<td class="tg-c3ow">A.</td>
<td class="tg-0pky">$\mathrm{Fe}_4\left[\mathrm{Fe}(\mathrm{CN})_6\right]_3 \cdot \mathrm{xH_2O}$</td>
<td class="tg-c3ow">III.</td>
<td class="tg-0pky">Prussian Blue</td>
</tr>
<tr>
<td class="tg-c3ow">B.</td>
<td class="tg-0pky">$\left[\mathrm{Fe}(\mathrm{CN})_5 \mathrm{NOS}\right]^{4-}$</td>
<td class="tg-c3ow">I.</td>
<td class="tg-0pky">Violet</td>
</tr>
<tr>
<td class="tg-c3ow">C.</td>
<td class="tg-0pky">$[\mathrm{Fe}(\mathrm{SCN})]^{2+}$</td>
<td class="tg-c3ow">II.</td>
<td class="tg-0pky">Blood Red</td>
</tr>
<tr>
<td class="tg-c3ow">D.</td>
<td class="tg-0pky">$\left(\mathrm{NH}_4\right)_3 \mathrm{PO}_4\cdot12 \mathrm{MoO}_3$</td>
<td class="tg-c3ow">IV.</td>
<td class="tg-0pky">Yellow</td>
</tr>
</tbody>
</table>
<p>Based on the analysis, the correct matching is:</p>
<p><strong>Option D: A-III, B-I, C-II, D-IV</strong></p>
About this question
Subject: Chemistry · Chapter: Coordination Compounds · Topic: Ligands and Coordination Number
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