Complex A has a composition of H12O6Cl3Cr. If the complex on treatment with conc.H2SO4
loses
13.5% of its original mass, the correct molecular formula of A is :
[Given: atomic mass of Cr = 52 amu and Cl = 35 amu]
Solution
Let x molecule of water are lost then
<br><br>13.5 = $$\left[ {{{x \times 18} \over {6 \times 18 + 3 \times 35 + 52}}} \right] \times 100$$
<br><br>$\Rightarrow$ x = 1.99 $\simeq$ 2
<br><br>$\therefore$ Around two moles of water are lost during
heating.
<br><br>$\therefore$ Formula of complex could be
<br><br> [Cr(H<sub>2</sub>O)<sub>4</sub>Cl<sub>2</sub>]Cl.2H<sub>2</sub>O
About this question
Subject: Chemistry · Chapter: Coordination Compounds · Topic: Ligands and Coordination Number
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