The complex that shows Facial - Meridional isomerism is :
Solution
<p>$\mathrm{Ma}_3 \mathrm{~b}_3$ type complexes show Facial - Meridional isomerism</p>
<p>(i) $\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_3 \mathrm{Cl}_3\right] \Rightarrow \mathrm{Ma}_3 \mathrm{~b}_3$</p>
<p>(ii) $\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_4 \mathrm{Cl}_2\right]^{+} \Rightarrow \mathrm{Ma}_4 \mathrm{~b}_2$</p>
<p>(iii) $\left[\mathrm{Co}(\mathrm{en})_3\right]^{3+} \quad \Rightarrow \mathrm{M}(\mathrm{AA})_3$</p>
<p>(iv) $\left[\mathrm{Co}(\mathrm{en})_2 \mathrm{Cl}_2\right]^{+} \Rightarrow \mathrm{M}(\mathrm{AA})_2 \mathrm{~b}_2$</p>
<p>$\mathrm{a,b},=\mathrm{NH}_3, \mathrm{Cl}^{-}$</p>
<p>$\mathrm{AA}=\mathrm{en}$</p>
About this question
Subject: Chemistry · Chapter: Coordination Compounds · Topic: Ligands and Coordination Number
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