The number of geometrical isomers for a square planar complex [Ma₂bc] (where a, b, c are different) is $x$.
Answer (integer)
3
Solution
For [Ma₂bc] square planar: 3 isomers — trans-aa, cis-ab (two orientations giving different isomers when b≠c). Actually there are 3 distinct arrangements.
About this question
Subject: Chemistry · Chapter: Coordination Compounds · Topic: Isomerism in Coordination Compounds
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