The number of unpaired electrons in [Fe(CN)₆]⁴⁻ (Fe is in +2 oxidation state) is $x$.
Answer (integer)
0
Solution
Fe²⁺ is d⁶. CN⁻ is strong field → pairs electrons in t₂g. All 6 electrons paired → 0 unpaired electrons (diamagnetic).
About this question
Subject: Chemistry · Chapter: Coordination Compounds · Topic: Crystal Field Theory
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