The number of words in the IUPAC name "potassium hexacyanoferrate(II)" is $x$. Count: potassium(1) hexacyanoferrate(2) II(3). Find $x$.
Answer (integer)
3
Solution
The three words are: potassium, hexacyanoferrate(II), and II (though II is a suffix). Actually "potassium hexacyanoferrate(II)" has 3 parts: potassium-hexacyanoferrate(II)-II. $x = 3$.
About this question
Subject: Chemistry · Chapter: Coordination Compounds · Topic: IUPAC Nomenclature
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