Given below are two statements :
Statement I : $\mathrm{PF}_5$ and $\mathrm{BrF}_5$ both exhibit $\mathrm{sp}^3 \mathrm{~d}$ hybridisation.
Statement II : Both $\mathrm{SF}_6$ and $[\mathrm{Co}(\mathrm{NH}_3)_6]^{3+}$ exhibit $\mathrm{sp}^3 \mathrm{~d}^2$ hybridisation.
In the light of the above statements, choose the correct answer from the options given below :
Solution
<p>Hybridisation of $\mathrm{P}$ in $\mathrm{PF}_5$ is $s p^3 d$ but the hybridisation of $\mathrm{Br}$ in $\mathrm{BrF}_5$ is $s p^3 d^2$. So, statement-I is false.</p>
<p>Hybridisation of $\mathrm{S}$ in $\mathrm{SF}_6$ is $s p^3 d^2$ but the hybridisation of $\mathrm{Co}^{3+}$ in $[\mathrm{Co}(\mathrm{NH}_3)_6]^{3+}$ is $d^2 s p^3$ as $\mathrm{NH}_3$ is a strong field ligand forcing the unpaired electrons to pair up. So, statement-II is false.</p>
About this question
Subject: Chemistry · Chapter: Coordination Compounds · Topic: Ligands and Coordination Number
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