Match List - I with List - II.
| List - I (Complex) | List - II (Primary valency and Secondary valency) |
|---|---|
| (A) [Co(en)2Cl2]Cl | (I) 3, 6 |
| (B) [Pt(NH3)2Cl(NO2)] | (II) 3, 4 |
| (C) Hg [Co(SCN)4] | (III) 2, 6 |
| (D) [Mg (EDTA)]2− | (IV) 2, 4 |
Choose the correct answer from the options given below :
Solution
<p>Primary valency $=$ Oxidation state</p>
<p>Secondary valency $=$ Co-ordination number</p>
<p><style type="text/css">
.tg {border-collapse:collapse;border-spacing:0;}
.tg td{border-color:black;border-style:solid;border-width:1px;font-family:Arial, sans-serif;font-size:14px;
overflow:hidden;padding:10px 5px;word-break:normal;}
.tg th{border-color:black;border-style:solid;border-width:1px;font-family:Arial, sans-serif;font-size:14px;
font-weight:normal;overflow:hidden;padding:10px 5px;word-break:normal;}
.tg .tg-c3ow{border-color:inherit;text-align:center;vertical-align:top}
.tg .tg-7btt{border-color:inherit;font-weight:bold;text-align:center;vertical-align:top}
.tg .tg-0pky{border-color:inherit;text-align:left;vertical-align:top}
</style>
<table class="tg" style="undefined;table-layout: fixed; width: 584px"><colgroup>
<col style="width: 79px">
<col style="width: 213px">
<col style="width: 129px">
<col style="width: 163px">
</colgroup>
<thead>
<tr>
<th class="tg-7btt"></th>
<th class="tg-7btt">Complex</th>
<th class="tg-7btt">Primary valency</th>
<th class="tg-7btt">Secondary</th>
</tr></thead>
<tbody>
<tr>
<td class="tg-c3ow">(A)</td>
<td class="tg-0pky">$\left[\mathrm{Co}(\mathrm{en})_2 \mathrm{Cl}_2\right] \mathrm{Cl}$</td>
<td class="tg-c3ow">3</td>
<td class="tg-c3ow">6</td>
</tr>
<tr>
<td class="tg-c3ow">(B)</td>
<td class="tg-0pky">$\left[\mathrm{Pt}\left(\mathrm{NH}_3\right)_2 \mathrm{Cl}\left(\mathrm{NO}_2\right)\right]$</td>
<td class="tg-c3ow">2</td>
<td class="tg-c3ow">4</td>
</tr>
<tr>
<td class="tg-c3ow">(C)</td>
<td class="tg-0pky">$\mathrm{Hg}\left[\mathrm{Co}(\mathrm{SCN})_4\right]$</td>
<td class="tg-c3ow">3</td>
<td class="tg-c3ow">4</td>
</tr>
<tr>
<td class="tg-c3ow">(D)</td>
<td class="tg-0pky">$[\mathrm{Mg}(\mathrm{EDTA})]^{2-}$</td>
<td class="tg-c3ow">2</td>
<td class="tg-c3ow">6</td>
</tr>
</tbody></table></p>
About this question
Subject: Chemistry · Chapter: Coordination Compounds · Topic: Ligands and Coordination Number
This question is part of PrepWiser's free JEE Main question bank. 173 more solved questions on Coordination Compounds are available — start with the harder ones if your accuracy is >70%.