Medium MCQ +4 / -1 PYQ · JEE Mains 2024

Yellow compound of lead chromate gets dissolved on treatment with hot $\mathrm{NaOH}$ solution. The product of lead formed is a :

  1. A Tetraanionic complex with coordination number six
  2. B Neutral complex with coordination number four
  3. C Dianionic complex with coordination number six
  4. D Dianionic complex with coordination number four Correct answer

Solution

<p>Lead chromate ( $\mathrm{PbCrO}_4$ ) dissolves in hot NaOH solution to form products due to a chemical reaction. The reaction involves the formation of a compound where lead ( $\mathrm{Pb}$ ) is coordinated by hydroxide ions ( $\mathrm{OH}^-$ ).</p> <p>The balanced chemical reaction is:</p> <p> $$\mathrm{PbCrO}_4 + 4\mathrm{NaOH} (hot, excess) \rightarrow \left[\mathrm{Pb}(\mathrm{OH})_4\right]^{2-} + \mathrm{Na}_2\mathrm{CrO}_4$$ </p> <p>In this reaction, lead forms a dianionic complex ( $\left[\mathrm{Pb}(\mathrm{OH})_4\right]^{2-}$ ) with hydroxide ions. This indicates that the lead is in the center of a complex with a coordination number of four, meaning it is directly bound to four hydroxide ions. Therefore, the correct description of the product formed with lead is a dianionic complex with a coordination number of four.</p>

About this question

Subject: Chemistry · Chapter: Coordination Compounds · Topic: Ligands and Coordination Number

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