(a) CoCl3.4NH3, (b) CoCl3.5NH3, (c) CoCl3.6NH3 and (d) CoCl(NO3)2.5NH3.
Number of complex(es) which will exist in cis-trans form is/are _______________.
Answer (integer)
1
Solution
$\mathrm{CoCl}_{3} \cdot 4 \mathrm{NH}_{3} \Rightarrow\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{Cl}_{2}\right] \mathrm{Cl}$
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$\mathrm{CoCl}_{3} \cdot 5 \mathrm{NH}_{3} \Rightarrow\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5} \mathrm{Cl}\right] \mathrm{Cl}_{2}$
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$\mathrm{CoCl}_{3} \cdot 6 \mathrm{NH}_{3} \Rightarrow\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right] \mathrm{Cl}_{3}$
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Only $\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{Cl}_{2}\right]$ can show geometrical isomerism. Hence can exist in cis-trans form.
About this question
Subject: Chemistry · Chapter: Coordination Compounds · Topic: Ligands and Coordination Number
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