The ratio of number of water molecules in Mohr's salt and potash alum is ____________ $\times$ 10$-$1. (Integer answer)
Answer (integer)
5
Solution
Mohr's salt : (NH<sub>4</sub>)<sub>2</sub> Fe(SO<sub>4</sub>)<sub>2</sub> . 6H<sub>2</sub>O<br><br>The number of water molecules in Mohr's salt = 6<br><br>Potash alum : KAl(SO<sub>4</sub>)<sub>2</sub> . 12H<sub>2</sub>O<br><br>The number of water molecules in potash alum = 12<br><br>So ratio of number of water molecules in Mohr's salt and potash alum <br><br>$= {6 \over {12}}$<br><br>$= {1 \over 2}$<br><br>= 0.5<br><br>= 5 $\times$ 10<sup>$-$1</sup>
About this question
Subject: Chemistry · Chapter: Coordination Compounds · Topic: Ligands and Coordination Number
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