Medium MCQ +4 / -1 PYQ · JEE Mains 2023

Match List I with List II:

List I (Complexes) List II (Hybridisation)
A. $\left[\mathrm{Ni}(\mathrm{CO})_{4}\right]$ I. $\mathrm{sp}^{3}$
B. $\left[\mathrm{Cu}\left(\mathrm{NH}_{3}\right)_{4}\right]^{2+}$ II. dsp$^{2}$
C. $\left[\mathrm{Fe}\left(\mathrm{NH}_{3}\right)_{6}\right]^{2+}$ III. $\mathrm{sp}^{3}\mathrm{d}^{2}$
D. $\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}$ IV. $\mathrm{d}^{2} \mathrm{sp}^{3}$

  1. A A-I, B-II, C-III, D-IV
  2. B A-II, B-I, C-III, D-IV
  3. C A-I, B-II, C-IV, D-III Correct answer
  4. D A-II, B-I, C-IV, D-III

Solution

<p>$\mathrm{Ni{(CO)_4}\buildrel {} \over \longrightarrow s{p^3}}$</p> <p>$$\mathrm{{\left[ {Cu{{(N{H_3})}_4}} \right]^{2 + }}\buildrel {} \over \longrightarrow ds{p^2}}$$</p> <p>$$\mathrm{{\left[ {Fe{{(N{H_3})}_6}} \right]^{2 + }}\buildrel {} \over \longrightarrow {d^2}s{p^3}}$$</p> <p>$$\mathrm{{\left[ {Fe{{({H_2}O)}_6}} \right]^{2 + }}\buildrel {} \over \longrightarrow s{p^3}{d^2}}$$</p>

About this question

Subject: Chemistry · Chapter: Coordination Compounds · Topic: Ligands and Coordination Number

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