The spin only magnetic moment ( $\mu$ ) value (B.M.) of the compound with strongest oxidising power among $\mathrm{Mn}_2 \mathrm{O}_3, \mathrm{TiO}$ and VO is ____________ B.M. (Nearest integer).
Answer (integer)
5
Solution
<p>The compound with the strongest oxidizing power among Mn₂O₃, TiO, and VO is Mn₂O₃. This conclusion is based on the standard electrode potential ($ E^\circ $) value:</p>
<p>$ E_{\text{Mn}^{+3} / \text{Mn}^{+2}}^\circ = +1.57 \, \text{V} $</p>
<p>For Mn³⁺, the electronic configuration is $ d^4 $. The spin-only magnetic moment ($ \mu $) is calculated as follows:</p>
<p>$ \mu = \sqrt{n(n+2)} \, \text{BM} $</p>
<p>Where $ n $ is the number of unpaired electrons. Here, $ n = 4 $:</p>
<p>$ \mu = \sqrt{4(4+2)} = \sqrt{24} \, \text{BM} $</p>
<p>This calculates to approximately 4.89 BM, which rounds to an integer value of 5 BM.</p>
About this question
Subject: Chemistry · Chapter: Coordination Compounds · Topic: Ligands and Coordination Number
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