Reaction of [Co(H2O)6]2+ with excess ammonia and in the presence of oxygen results into a diamagnetic product. Number of electrons present in t2g-orbitals of the product is ___________.
Answer (integer)
6
Solution
$\left[\mathrm{Co}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{+2} \underset{\mathrm{O}_{2}}{\stackrel{\mathrm{NH}_{3}}{\longrightarrow}}\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right]^{+3}+e^{-}$
<br/><br/>
$\mathrm{Co}^{+3} \longrightarrow 3 \mathrm{~d}^{6}$
<br/><br/>
$\mathrm{NH}_{3}$ is a strong field ligand.
<br/><br/>
$$
3 \mathrm{~d}^{6} \longrightarrow \mathrm{t}_{2 \mathrm{~g}}^{6} ~\mathrm{eg}^{\circ}
$$
About this question
Subject: Chemistry · Chapter: Coordination Compounds · Topic: Ligands and Coordination Number
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