$\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_6\right]^{3+}$ and $\left[\mathrm{CoF}_6\right]^{3-}$ are respectively known as :
Solution
$\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_6\right]^{3+}$
<br/><br/>$\mathrm{Co}^{3+}($ strong field ligand $) \Rightarrow 3 \mathrm{~d}^6\left(\mathrm{t}_{2 \mathrm{~g}}^6, \mathrm{e}_{\mathrm{g}}^0\right)$,
<br/><br/>Hybridisation : $\mathrm{d}^2 \mathrm{sp}^3$
<br/><br/>Inner obital complex(spin paired complex)
<br/><br/>Pairing will take place.
<br/><br/>$\left[\mathrm{CoF}_6\right]^{3-}$
<br/><br/>$\mathrm{Co}^{3+}($ weak field ligand $) \Rightarrow 3 \mathrm{~d}^6\left(\mathrm{t}_{2 \mathrm{~g}}^4, \mathrm{e}_{\mathrm{g}}^2\right)$
<br/><br/>Hybridisation : $\mathrm{sp}^3 \mathrm{~d}^2$
<br/><br/>Outer orbital complex (spin free complex)
<br/><br/>No pairing will take place
About this question
Subject: Chemistry · Chapter: Coordination Compounds · Topic: Ligands and Coordination Number
This question is part of PrepWiser's free JEE Main question bank. 173 more solved questions on Coordination Compounds are available — start with the harder ones if your accuracy is >70%.