Given below are two statements :
Statement I : [Ni(CN)4]2$-$ is square planar and diamagnetic complex, with dsp2 hybridization for Ni but [Ni(CO)4] is tetrahedral, paramagnetic and with sp3-hybridication for Ni.
Statement II : [NiCl4]2$-$ and [Ni(CO)4] both have same d-electron configuration have same geometry and are paramagnetic.
In light the above statements, choose the correct answer from the options given below :
Solution
[Ni(CN)<sub>4</sub>]<sup>2–</sup> : d<sup>8</sup> configuration, SFL, sq. planar splitting (dsp<sup>2</sup>), diamagnetic.<br/><br/>
[Ni(CO)<sub>4</sub>] : d<sup>10</sup> config (after excitation), SFL, tetrahedral splitting (sp<sup>3</sup>), diamagnetic. <br/><br/>
[NiCl<sub>4</sub>]<sup>2–</sup> : d<sup>8</sup> config, WFL, tetrahedral splitting (sp<sup>3</sup>), paramagnetic(2 unpaired e<sup>–</sup>).
About this question
Subject: Chemistry · Chapter: Coordination Compounds · Topic: Ligands and Coordination Number
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