The total number of unpaired electrons present in [Co(NH3)6]Cl2 and [Co(NH3)6]Cl3 is :
Answer (integer)
3
Solution
[Co(NH<sub>3</sub>)<sub>6</sub>]Cl<sub>2</sub><br><br>Co<sup>2+</sup> : [Ar]3d<sup>7</sup>4s<sup>0</sup>4p<sup>0</sup><br><br>For this complex $\Delta$<sub>0</sub> < P.E., so pairing of electron does not take place.<br><br>sp<sup>3</sup>d<sup>2</sup> hybridisation<br><br>Total 3 unpaired electrons are present.<br><br>[Co(NH<sub>3</sub>)<sub>6</sub>]Cl<sub>3</sub><br><br>Co<sup>3+</sup> : [Ar]3d<sup>6</sup> 4s<sup>0</sup> 4p<sup>0</sup><br><br>d<sup>2</sup>sp<sup>3</sup> hybridistion<br><br>NH<sub>3</sub> acts as SFL because $\Delta$<sub>0</sub> > P.E.<br><br>So, here all electrons becomes paired.
About this question
Subject: Chemistry · Chapter: Coordination Compounds · Topic: Ligands and Coordination Number
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