1 mol of an octahedral metal complex with formula MCl3 . 2L on reaction with excess of AgNO3 gives 1 mol of AgCl. The denticity of Ligand L is ____________. (Integer answer)
Answer (integer)
2
Solution
MCl<sub>3</sub> . 2L octahedral<br><br>$$\mathop {MC{l_3}.2L}\limits_{1\,mole} \buildrel {Ex.\,AgN{O_3}} \over
\longrightarrow $$ 1 mole of AgCl<br><br>Its means that one Cl<sup>$-$</sup> ion present in ionization sphere.<br><br>$\therefore$ formula = [MCl<sub>2</sub>L<sub>2</sub>]Cl<br><br>For octahedral complex coordination no. is 6<br><br>$\therefore$ L act as bidentate ligand
About this question
Subject: Chemistry · Chapter: Coordination Compounds · Topic: Ligands and Coordination Number
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