The difference in the 'spin-only' magnetic moment values of $\mathrm{KMnO}_4$ and the manganese product formed during titration of $\mathrm{KMnO}_4$ against oxalic acid in acidic medium is ________ $\mathrm{BM}$. (nearest integer)
Answer (integer)
6
Solution
<p>The 'spin-only' magnetic moment for $\mathrm{Mn}^{7+}$ is $0$ BM. During the titration of $\mathrm{KMnO}_4$ with oxalic acid in an acidic medium, manganese is reduced to $\mathrm{Mn}^{2+}$, which has a 'spin-only' magnetic moment of $5.91$ BM.</p>
<p>Thus, the difference in magnetic moment values is calculated as follows:</p>
<p>$0 \, \text{BM}$ (for $\mathrm{Mn}^{7+}$) subtracted from $5.91 \, \text{BM}$ (for $\mathrm{Mn}^{2+}$), which results in $5.91 \, \text{BM}$.</p>
<p>Rounding this to the nearest integer, we get a difference of approximately $6$ BM.</p>
About this question
Subject: Chemistry · Chapter: Coordination Compounds · Topic: Ligands and Coordination Number
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