The IUPAC name of $$\mathrm{K}_{3}\left[\mathrm{Co}\left(\mathrm{C}_{2} \mathrm{O}_{4}\right)_{3}\right]$$ is:-

<p>To determine the IUPAC name of the compound K₃[Co(C₂O₄)₃], let's follow the nomenclature rules for coordination compounds:</p> <p><p><strong>Identify the Cation and Anion</strong>: The compound consists of potassium ions (K⁺) and a complex anion [Co(C₂O₄)₃]³⁻.</p></p> <p><p><strong>Name the Cation First</strong>: The cation is named first. So, we start with "Potassium."</p></p> <p><p><strong>Determine the Ligand Name</strong>: The ligand C₂O₄²⁻ is called "oxalato."</p></p> <p><p><strong>Count the Number of Ligands</strong>: There are three oxalato ligands. Since "oxalato" does not contain any numerical prefixes (like di-, tri-), we use the prefixes "di-", "tri-", etc., for simple ligands. So, we use "trioxalato."</p></p> <p><p><strong>Name the Central Metal Atom</strong>: Since the complex ion is an anion, the metal name ends with the suffix "-ate." Therefore, "cobalt" becomes "cobaltate."</p></p> <p><p><strong>Specify the Oxidation State</strong>: The oxidation state of cobalt in this complex can be calculated:</p></p> <p><p>Let the oxidation state of Co be x.</p></p> <p><p>Each oxalato ligand has a charge of -2.</p></p> <p><p>The overall charge of the complex ion is -3.</p> <p>So, x + 3(-2) = -3 ⇒ x -6 = -3 ⇒ x = +3.</p> <p>Therefore, we indicate the oxidation state as (III).</p></p> <p>Combining all these, the IUPAC name is <strong>Potassium trioxalatocobaltate(III)</strong>.</p> <p><strong>Answer:</strong> Option C</p> <p>Potassium trioxalatocobaltate(III)</p>