Total number of unpaired electrons in the complex ions $[\mathrm{Co}(\mathrm{NH}_3)_6]^{3+}$ and $[\mathrm{NiCl}_4]^{2-}$ is ________.
Answer (integer)
2
Solution
<p>$$\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_6\right]^{3+}: \mathrm{Co}^{3+}: \mathrm{t}_{2 \mathrm{~g}}^6 \mathrm{e}_{\mathrm{g}}^0: \mathrm{n}=0$$</p>
<p>$$\left[\mathrm{NiCl}_4\right]^{2-}: \mathrm{Ni}^{2+}: t_{2 \mathrm{~g}}^6 \mathrm{e}_{\mathrm{g}}^2: \mathrm{n}=2$$</p>
About this question
Subject: Chemistry · Chapter: Coordination Compounds · Topic: Ligands and Coordination Number
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