The correct order of energy of absorption for the following metal complexes is :
A : [Ni(en)3]2+ , B : [Ni(NH3)6]2+ , C : [Ni(H2O)6]2+
Solution
Stronger is ligand attached to metal ion, greater will be the splitting between $\mathrm{t}_{2} \mathrm{g}$ and $e_g$ (hence greater will be $\Delta \mathrm{U})$<br/><br/>$\therefore$ Greater will be absorption of energy.<br/><br/> Hence correct order
<br/><br/>
$$\left[\mathrm{Ni}(\mathrm{en})_{3}\right]^{2+}>\left[\mathrm{Ni}\left(\mathrm{NH}_{3}\right)_{6}\right]^{2+}>\left[\mathrm{Ni}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}$$
About this question
Subject: Chemistry · Chapter: Coordination Compounds · Topic: Ligands and Coordination Number
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