Match List I with List II
| LIST I Coordination Complex |
LIST II Number of unpaired electrons |
||
|---|---|---|---|
| A. | $\left[\mathrm{Cr}(\mathrm{CN})_{6}\right]^{3-}$ | I. | 0 |
| B. | $\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}$ | II. | 3 |
| C. | $\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right]^{3+}$ | III. | 2 |
| D. | $\left[\mathrm{Ni}\left(\mathrm{NH}_{3}\right)_{6}\right]^{2+}$ | IV. | 4 |
Choose the correct answer from the options given below:
Solution
For option (A)<br/><br/>
$$
\begin{aligned}
& \mathrm{Cr}^{+3}: 3 \mathrm{~d}^3 \\\\
& \mathrm{CN}^{-} \rightarrow \mathrm{SFL}
\end{aligned}
$$<br/><br/>
No. of unpaired electrons $=3$<br/><br/>
For option (B)<br/><br/>
$$
\begin{aligned}
& \mathrm{Fe}^{+2}: 3 \mathrm{~d}^6 \\\\
& \mathrm{H}_2 \mathrm{O}: \mathrm{WFL}
\end{aligned}
$$<br/><br/>
No. of unpaired electrons $=4$<br/><br/>
For option (C)<br/><br/>
$$
\begin{aligned}
& \mathrm{Co}^{+3}: 3 \mathrm{~d}^6 \\\\
& \mathrm{NH}_3: \mathrm{SFL}
\end{aligned}
$$<br/><br/>
No. of unpaired electrons $=0$<br/><br/>
For option (D)<br/><br/>
$$
\begin{aligned}
& \mathrm{Ni}^{+2}: 3 \mathrm{~d}^8 \\\\
& \mathrm{NH}_3: \mathrm{SFL}
\end{aligned}
$$<br/><br/>
No. of unpaired electrons $=2$
About this question
Subject: Chemistry · Chapter: Coordination Compounds · Topic: Ligands and Coordination Number
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