If $\mathrm{Ni}^{2+}$ is replaced by $\mathrm{Pt}^{2+}$ in the complex $\left[\mathrm{NiCl}_{2} \mathrm{Br}_{2}\right]^{2-}$, which of the following properties are expected to get changed ?
A. Geometry
B. Geometrical isomerism
C. Optical isomerism
D. Magnetic properties
Solution
The complex $\left[\mathrm{NiCl}_{2} \mathrm{Br}_{2}\right]^{2-}$ is a tetrahedral complex due to the fact that Nickel (Ni) in this complex is in its +2 oxidation state, and thus adopts a dsp² hybridization, resulting in a tetrahedral geometry.
<br/><br/>If $\mathrm{Ni}^{2+}$ is replaced by $\mathrm{Pt}^{2+}$, the new complex would be $\left[\mathrm{PtCl}_{2} \mathrm{Br}_{2}\right]^{2-}$. Platinum (Pt) in its +2 oxidation state typically forms square planar complexes due to its preference for dsp² hybridization.
<br/><br/><ol>
<li><p><strong>Geometry</strong> :</p>
<ul>
<br/><li>$\left[\mathrm{NiBr}_2 \mathrm{Cl}_2\right]^{2-}$ is tetrahedral.</li>
<li>$\left[\mathrm{PtBr}_2 \mathrm{Cl}_2\right]^{2-}$ is square planar.</li>
<li>Thus, replacing $\mathrm{Ni}^{2+}$ with $\mathrm{Pt}^{2+}$ changes the geometry from tetrahedral to square planar.</li>
</ul>
</li>
<br/><li><p><strong>Geometrical Isomerism</strong> :</p>
<ul>
<br/><li>Tetrahedral complexes, like $\left[\mathrm{NiBr}_2 \mathrm{Cl}_2\right]^{2-}$, do not exhibit geometrical isomerism.</li>
<li>Square planar complexes, like $\left[\mathrm{PtBr}_2 \mathrm{Cl}_2\right]^{2-}$, can exhibit geometrical isomerism.</li>
<li>Therefore, geometrical isomerism would be introduced by replacing $\mathrm{Ni}^{2+}$ with $\mathrm{Pt}^{2+}$.</li>
</ul>
</li>
<br/><li><p><strong>Optical Isomerism</strong> :</p>
<ul>
<br/><li>Both the $\mathrm{Ni}$-based tetrahedral complex and the $\mathrm{Pt}$-based square planar complex are optically inactive. </li>
<li>Optical isomerism is not observed in either case.</li>
</ul>
</li>
<br/><li><p><strong>Magnetic Properties</strong> :</p>
<ul>
<br/><li>The magnetic properties depend on the electronic configuration of the central metal ion.</li>
<li>There will be a change in magnetic properties due to the different electronic configurations of $\mathrm{Ni}^{2+}$ and $\mathrm{Pt}^{2+}$.</li>
</ul>
</li>
</ol>
<p>Based on this information, the properties expected to change when $\mathrm{Ni}^{2+}$ is replaced by $\mathrm{Pt}^{2+}$ are:</p>
<ul>
<li>Geometry (from tetrahedral to square planar)</li>
<li>Geometrical Isomerism (introduced in the $\mathrm{Pt}$-based complex)</li>
<li>Magnetic Properties (due to different electronic configurations)</li>
</ul>
<p>Optical isomerism remains unchanged (inactive in both cases).</p>
<p>Therefore, the correct answer is :</p>
<p>Option B: A, B, and D (Geometry, Geometrical Isomerism, and Magnetic Properties).</p>
About this question
Subject: Chemistry · Chapter: Coordination Compounds · Topic: Ligands and Coordination Number
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