The sum of oxidation states of two silver ions in [Ag(NH3)2] [Ag(CN)2] complex is _____________.
Answer (integer)
2
Solution
[Ag(NH<sub>3</sub>)<sub>2</sub>][Ag(CN)<sub>2</sub>] complex dissociates into [Ag(NH<sub>3</sub>)<sub>2</sub>]<sup>+</sup> and [Ag(CN)<sub>2</sub>].<br/><br/>Oxidation of Ag in [Ag(NH<sub>3</sub>)<sub>2</sub>]<sup>+</sup><br/><br/>Ag + 0 $\times$ 2 = + 1<br/><br/>Ag = + 1<br/><br/>Oxidation state of Ag in [Ag(CN)<sub>2</sub>]<sup>$-$</sup><br/><br/>Ag + ($-$1) $\times$ 2 = $-$ 1<br/><br/>Ag $-$ 2 = $-$ 1<br/><br/>$\Rightarrow$ Ag = + 1<br/><br/>$\therefore$ Sum of oxidation states of two silver ions in [Ag(NH<sub>3</sub>)<sub>2</sub>][Ag(CN)<sub>2</sub>] complex is 2.
About this question
Subject: Chemistry · Chapter: Coordination Compounds · Topic: Ligands and Coordination Number
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