Arrange the following coordination compounds in the increasing order of magnetic moments. (Atomic numbers : Mn = 25; Fe = 26)
A. [FeF6]3$-$
B. [Fe(CN)6]3$-$
C. [MnCl6]3$-$ (high spin)
D. [Mn(CN)6]3$-$
Choose the correct answer from the options given below :
Solution
<style type="text/css">
.tg {border-collapse:collapse;border-spacing:0;}
.tg td{border-color:black;border-style:solid;border-width:1px;font-family:Arial, sans-serif;font-size:14px;
overflow:hidden;padding:10px 5px;word-break:normal;}
.tg th{border-color:black;border-style:solid;border-width:1px;font-family:Arial, sans-serif;font-size:14px;
font-weight:normal;overflow:hidden;padding:10px 5px;word-break:normal;}
.tg .tg-1wig{font-weight:bold;text-align:left;vertical-align:top}
.tg .tg-0lax{text-align:left;vertical-align:top}
</style>
<table class="tg">
<thead>
<tr>
<th>Coordination Compound</th>
<th>Number of unpaired e<sup>–</sup> (n)</th>
<th>Magnetic moment (µ) (B.M)</th>
</tr>
</thead>
<tbody>
<tr>
<td>A. [FeF<sub>6</sub>]<sup>3$-$</sup> - d<sup>5</sup></td>
<td>5</td>
<td>5.91</td>
</tr>
<tr>
<td>B. [Fe(CN)<sub>6</sub>]<sup>3$-$</sup> - d<sup>5</sup></td>
<td>1</td>
<td>1.73</td>
</tr>
<tr>
<td>C. [MnCl<sub>6</sub>]<sup>3$-$</sup> - d<sup>4</sup></td>
<td>4</td>
<td>4.89</td>
</tr>
<tr>
<td>D. [Mn(CN)<sub>6</sub>]<sup>3$-$</sup> - d<sup>4</sup></td>
<td>2</td>
<td>2.82</td>
</tr>
</tbody>
</table><br/>
Hence, correct order of magnetic moment is $2 < 4 < 3 < 1$
About this question
Subject: Chemistry · Chapter: Coordination Compounds · Topic: Ligands and Coordination Number
This question is part of PrepWiser's free JEE Main question bank. 173 more solved questions on Coordination Compounds are available — start with the harder ones if your accuracy is >70%.