[Ti(H2O)6]3+ absorbs light of wavelength 498 nm during a d $-$ d transition. The octahedral splitting energy for the above complex is ____________ $\times$ 10$-$19 J. (Round off to the Nearest Integer). h = 6.626 $\times$ 10$-$34 Js; c = 3 $\times$ 108 ms$-$1
Answer (integer)
4
Solution
Octahedral splitting energy = ${{hc} \over \lambda }$<br><br>$$ = {{6.626 \times {{10}^{ - 34}} \times 3 \times {{10}^8}} \over {498 \times {{10}^{ - 9}}}}$$<br><br>$= 3.99 \times {10^{ - 19}}J$<br><br>$\approx 4 \times {10^{ - 19}}$
About this question
Subject: Chemistry · Chapter: Coordination Compounds · Topic: Ligands and Coordination Number
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