An elevator in a building can carry a maximum of 10 persons, with the average mass of each person being 68 kg, The mass of the elevator itself is 920 kg and it moves with a constant speed of 3 m/s. The frictional force opposing the motion is 6000 N. If the elevator is moving up with its full capacity, the power delivered by the motor to the elevator (g = 10 m/s2) must be at least :
Solution
Net force on motor will be
<br><br>F<sub>m</sub> = [920 + 68(10)]g + 6000
= 22000 N
<br><br>So, required power for motor
<br><br>P = F<sub>m</sub>.V = 22000$\times$3 = 66000 W
About this question
Subject: Physics · Chapter: Work, Energy and Power · Topic: Work Done by a Force
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