A bag of sand of mass 9.8 kg is suspended by a rope. A bullet of 200 g travelling with speed 10 ms$-$1 gets embedded in it, then loss of kinetic energy will be :
Solution
<p>Loss in $KE = {1 \over 2} \times {{{m_1}{m_2}} \over {{m_1} + {m_2}}} \times {v^2}$</p>
<p>$= {1 \over 2} \times {{9.8 \times 0.2} \over {10}} \times {(10)^2}$</p>
<p>$= 9.8$ J</p>
About this question
Subject: Physics · Chapter: Work, Energy and Power · Topic: Work Done by a Force
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