"A particle of mass 500 gm is moving in a straight line with velocity v = b x5/2. The work done by the net force during its displacement from x = 0 to x = 4 m is : (Take b = 0.25 m$-$3/2 s$-$1)."

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${W_{total}} = \Delta K$

$$ = {1 \over 2}\left( {{1 \over 2}} \right)\left[ {{{\{ b{{(4)}^{5/2}}\} }^2} - 0} \right]$$

$= {{{b^2}} \over 4} \times {4^5}$

$\Rightarrow {W_{total}} = 16\,J$

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A particle of mass 500 gm is moving in a straight line with velocity v = b x^5/2. The work done by the net force during its displacement from x = 0 to x = 4 m is : (Take b = 0.25 m^$-$3/2 s^$-$1).

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A particle of mass 500 gm is moving in a straight line with velocity v = b x5/2. The work done by the net force during its displacement from x = 0 to x = 4 m is : (Take b = 0.25 m$-$3/2 s$-$1).

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A particle of mass 500 gm is moving in a straight line with velocity v = b x^5/2. The work done by the net force during its displacement from x = 0 to x = 4 m is : (Take b = 0.25 m^$-$3/2 s^$-$1).