A simple pendulum of length $L$ is released from rest at height $h$ above the mean position. Its speed at the lowest point is:

1. A $\sqrt{gh}$
2. B $\sqrt{2gh}$ Correct answer
3. C $gh$
4. D $2gh$

Solution

$\frac{1}{2}mv^2 = mgh \Rightarrow v = \sqrt{2gh}$.

About this question

Subject: Physics · Chapter: Work, Energy and Power · Topic: Conservation of Energy

This question is part of PrepWiser's free JEE Main question bank. 15 more solved questions on Work, Energy and Power are available — start with the harder ones if your accuracy is >70%.

More Work, Energy and Power questions

• Easy MCQ

  The coefficient of restitution for a perfectly elastic collision is:

• Medium MCQ

  Two bodies of equal mass undergo a one-dimensional elastic collision, with one initially at rest. After the collision:

• Easy MCQ

  In a perfectly inelastic collision, which quantity is conserved?

• Medium MCQ

  Instantaneous power in terms of force $\vec F$ and velocity $\vec v$ is:

• Easy MCQ

  A man does 1000 J of work in 10 s. His average power is: