A siren emitting at 600 Hz approaches a stationary observer at 30 m/s. If the speed of sound is 330 m/s, the observed frequency is:
Solution
$f' = f \cdot v/(v - v_s) = 600 \times 330/300 = 660$ Hz.
About this question
Subject: Physics · Chapter: Waves · Topic: Doppler Effect
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