Medium MCQ +4 / -1

A siren emitting at 600 Hz approaches a stationary observer at 30 m/s. If the speed of sound is 330 m/s, the observed frequency is:

  1. A 660 Hz Correct answer
  2. B 550 Hz
  3. C 720 Hz
  4. D 500 Hz

Solution

$f' = f \cdot v/(v - v_s) = 600 \times 330/300 = 660$ Hz.

About this question

Subject: Physics · Chapter: Waves · Topic: Doppler Effect

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