"The excess pressure inside a liquid drop is 500 Nm$-$2. If the radius of the drop is 2 mm, the surface tension of liquid is x $\times$ 10$-$3 Nm$-$1. The value of x is _____________."

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Accepted Answer

"$\mathrm{P}=\mathrm{P}_{0}+\frac{2 T}{R} $

$\Rightarrow P-P_{0}=\frac{2 T}{R}$

$$ \begin{aligned} &500=\frac{2 \times T}{2 \times 10^{-3}} \\\\ &T=500 \times 10^{-3} \\\\ &\text { So, } x=500 \end{aligned} $$"

The excess pressure inside a liquid drop is 500 Nm^$-$2. If the radius of the drop is 2 mm, the surface tension of liquid is x $\times$ 10^$-$3 Nm^$-$1. The value of x is _____________.

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The excess pressure inside a liquid drop is 500 Nm$-$2. If the radius of the drop is 2 mm, the surface tension of liquid is x $\times$ 10$-$3 Nm$-$1. The value of x is _____________.

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The excess pressure inside a liquid drop is 500 Nm^$-$2. If the radius of the drop is 2 mm, the surface tension of liquid is x $\times$ 10^$-$3 Nm^$-$1. The value of x is _____________.