A hydraulic press can lift 100 kg when a mass 'm' is placed on the smaller piston. It can lift ___________ kg when the diameter of the larger piston is increased by 4 times and that of the smaller piston is decreased by 4 times keeping the same mass 'm' on the smaller piston.
Answer (integer)
25600
Solution
According to Pascal's law,<br/><br/>${{{F_1}} \over {{A_1}}} = {{{F_2}} \over {{A_2}}}$<br/><br/>Initially, ${{100g} \over {{A_1}}} = {{mg} \over {{A_2}}}$ .... (i)<br/><br/>Finally, ${{Mg} \over {16{A_1}}} = {{mg} \over {\left( {{{{A_2}} \over {16}}} \right)}}$ ..... (ii)<br/><br/>On dividing Eqs. (i) by (ii), we get<br/><br/>${{100 \times 16} \over M} = {1 \over {16}}$<br/><br/>$\therefore$ M = 25600 kg
About this question
Subject: Physics · Chapter: Properties of Solids and Liquids · Topic: Elasticity
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