Easy MCQ +4 / -1 PYQ · JEE Mains 2024

Correct Bernoulli's equation is (symbols have their usual meaning) :

  1. A $P+\frac{1}{2} \rho g h+\frac{1}{2} \rho v^2=$ constant
  2. B $P+m g h+\frac{1}{2} m v^2=$ constant
  3. C $P+\rho g h+\rho v^2=$ constant
  4. D $P+\rho g h+\frac{1}{2} \rho v^2=$ constant Correct answer

Solution

<p>Bernoulli's equation relates the pressure, velocity, and height in a flowing fluid and is derived from the principle of conservation of energy. The correct form of Bernoulli's equation is:</p> <p>$P + \rho g h + \frac{1}{2} \rho v^2 = \text{constant}$</p> <p>where:</p> <ul> <li><b>P</b> is the pressure within the fluid.</li> <li><b>$\rho$</b> is the density of the fluid.</li> <li><b>g</b> is the acceleration due to gravity.</li> <li><b>h</b> is the height above a reference point.</li> <li><b>v</b> is the velocity of the fluid.</li> </ul> <p>Looking at the options given:</p> <ol> <li>Option A: $P + \frac{1}{2} \rho g h + \frac{1}{2} \rho v^2 = \text{constant}$</li> <li>Option B: $P + m g h + \frac{1}{2} m v^2 = \text{constant}$</li> <li>Option C: $P + \rho g h + \rho v^2 = \text{constant}$</li> <li>Option D: $P + \rho g h + \frac{1}{2} \rho v^2 = \text{constant}$</li> </ol> <p>Option D correctly represents Bernoulli's equation in its proper form. Therefore, the correct answer is:</p> <p><b>Option D</b></p>

About this question

Subject: Physics · Chapter: Properties of Solids and Liquids · Topic: Elasticity

This question is part of PrepWiser's free JEE Main question bank. 183 more solved questions on Properties of Solids and Liquids are available — start with the harder ones if your accuracy is >70%.

Drill 25 more like these. Every day. Free.

PrepWiser turns these solved questions into a daily practice loop. Chapter-wise drills, full mocks, AI doubt chat. No auto-renew.

Start free →