A 100 m long wire having cross-sectional area $\mathrm{6.25\times10^{-4}~m^2}$ and Young's modulus is $\mathrm{10^{10}~Nm^{-2}}$ is subjected to a load of 250 N, then the elongation in the wire will be :
Solution
Elongation in wire $\delta=\frac{\mathrm{F} \ell}{\mathrm{AY}}$<br/><br/>
$$
\begin{aligned}
& \delta=\frac{250 \times 100}{6.25 \times 10^{-4} \times 10^{10}} \\\\
& \delta=4 \times 10^{-3} \mathrm{~m}
\end{aligned}
$$
About this question
Subject: Physics · Chapter: Properties of Solids and Liquids · Topic: Elasticity
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