An object is located at 2 km beneath the surface of the water. If the fractional compression ${{\Delta V} \over V}$ is 1.36%, the ratio of hydraulic stress to the corresponding hydraulic strain will be ____________. [Given : density of water is 1000 kgm$-$3 and g = 9.8 ms$-$2]
Solution
$\beta = {{\Delta p} \over {{{\Delta V} \over V}}}$<br><br>$\Rightarrow$ $$\beta = {{\Delta \rho gh} \over {{{\Delta V} \over V}}} = {{1000 \times 9.8 \times 2 \times {{10}^3}} \over {{{1.36} \over {100}}}}$$<br><br>$\Rightarrow$ $\beta$ = 1.44 $\times$ 10<sup>9</sup> N/m<sup>2</sup>
About this question
Subject: Physics · Chapter: Properties of Solids and Liquids · Topic: Elasticity
This question is part of PrepWiser's free JEE Main question bank. 183 more solved questions on Properties of Solids and Liquids are available — start with the harder ones if your accuracy is >70%.