Match List I with List II

	List I		List II
A.	Surface tension	I.	$\mathrm{kg~m^{-1}~s^{-1}}$
B.	Pressure	II.	$\mathrm{kg~ms^{-1}}$
C.	Viscosity	III.	$\mathrm{kg~m^{-1}~s^{-2}}$
D.	Impulse	IV.	$\mathrm{kg~s^{-2}}$

Choose the correct answer from the options given below :

$$ \begin{aligned} \text { (A) } \text { Surface Tension }=\frac{\mathrm{F}}{\ell} & =\frac{\mathrm{MLT}^{-2}}{\mathrm{~L}}=\mathrm{ML}^{0} \mathrm{~T}^{-2} \\\\ & =\mathrm{kg\,s}^{-2}(\mathrm{IV}) \end{aligned} $$<br/><br/> $$ \begin{aligned} & \text { (B) Pressure }=\frac{F}{\mathrm{~A}}=\frac{\mathrm{MLT}^{-2}}{\mathrm{~L}^2} \\\\ & =\mathrm{kg} \,\mathrm{m}^{-1} \mathrm{~s}^{-2}(\mathrm{III}) \end{aligned} $$<br/><br/> $\begin{aligned} \text { (C) Viscosity } & =\frac{\mathrm{F}}{\mathrm{A}\left(\frac{\mathrm{dV}}{\mathrm{dz}}\right)}=\frac{\mathrm{MLT}^{-2}}{\mathrm{~L}^2\left(\frac{\mathrm{LT}^{-1}}{\mathrm{~L}}\right)} \\\\ & =\mathrm{ML}^{-1} \mathrm{~T}^{-1}=\mathrm{kg} \,\mathrm{m}^{-1} \mathrm{~s}^{-1}(\mathrm{I})\end{aligned}$ <br/><br/>$$ \begin{aligned} \text { (D) } \text { Impulse } & =\int F d t=\mathrm{MLT}^{-2} \times \mathrm{T} \\\\ & =\mathrm{MLT}^{-1}=\mathrm{kg\,ms}^{-1} \text { (II) } \end{aligned} $$