The frequency ($\nu$) of an oscillating liquid drop may depend upon radius ($r$) of the drop, density ($\rho$) of liquid and the surface tension (s) of the liquid as $\nu=r^a\rho^b s^c$. The values of a, b and c respectively are
Solution
$[v]=\left[\mathrm{T}^{-1}\right]$
<br/><br/>
$$
\begin{aligned}
& {[r]=\mathrm{L} \quad[s]=\left[\frac{\mathrm{MLT}^{-2}}{\mathrm{~L}}\right]} \\\\
& {[\rho]=\left[\frac{\mathrm{M}}{\mathrm{L}^{3}}\right]=\left[\mathrm{ML}^{-3}\right]} \\\\
& \Rightarrow v=r^{a} \rho^{b} \mathrm{~s}^{c} \\\\
& \Rightarrow \mathrm{T}^{-1}=\mathrm{L}^{a} \mathrm{M}^{b} \mathrm{~L}^{-3 b} \mathrm{M}^{c} \mathrm{~T}^{-2 c} \\\\
& \Rightarrow \mathrm{T}^{-1}=\mathrm{M}^{(b+c)} \mathrm{L}^{(a-3 b)} \mathrm{T}^{-2 c} \\\\
& -2 c=-1 \Rightarrow c=\frac{1}{2} \\\\
& b+c=0 \\\\
& \Rightarrow b=-\frac{1}{2} \\\\
& a-3 b=0 \Rightarrow 3 b=a \Rightarrow a=-\frac{3}{2} \\\\
& (a, b, c)=\left(-\frac{3}{2},-\frac{1}{2}, \frac{1}{2}\right)
\end{aligned}
$$
About this question
Subject: Physics · Chapter: Properties of Solids and Liquids · Topic: Elasticity
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