Medium MCQ +4 / -1 PYQ · JEE Mains 2023

The frequency ($\nu$) of an oscillating liquid drop may depend upon radius ($r$) of the drop, density ($\rho$) of liquid and the surface tension (s) of the liquid as $\nu=r^a\rho^b s^c$. The values of a, b and c respectively are

  1. A $\left( {{3 \over 2},{1 \over 2}, - {1 \over 2}} \right)$
  2. B $\left( { - {3 \over 2}, - {1 \over 2},{1 \over 2}} \right)$ Correct answer
  3. C $\left( {{3 \over 2}, - {1 \over 2},{1 \over 2}} \right)$
  4. D $\left( { - {3 \over 2},{1 \over 2},{1 \over 2}} \right)$

Solution

$[v]=\left[\mathrm{T}^{-1}\right]$ <br/><br/> $$ \begin{aligned} & {[r]=\mathrm{L} \quad[s]=\left[\frac{\mathrm{MLT}^{-2}}{\mathrm{~L}}\right]} \\\\ & {[\rho]=\left[\frac{\mathrm{M}}{\mathrm{L}^{3}}\right]=\left[\mathrm{ML}^{-3}\right]} \\\\ & \Rightarrow v=r^{a} \rho^{b} \mathrm{~s}^{c} \\\\ & \Rightarrow \mathrm{T}^{-1}=\mathrm{L}^{a} \mathrm{M}^{b} \mathrm{~L}^{-3 b} \mathrm{M}^{c} \mathrm{~T}^{-2 c} \\\\ & \Rightarrow \mathrm{T}^{-1}=\mathrm{M}^{(b+c)} \mathrm{L}^{(a-3 b)} \mathrm{T}^{-2 c} \\\\ & -2 c=-1 \Rightarrow c=\frac{1}{2} \\\\ & b+c=0 \\\\ & \Rightarrow b=-\frac{1}{2} \\\\ & a-3 b=0 \Rightarrow 3 b=a \Rightarrow a=-\frac{3}{2} \\\\ & (a, b, c)=\left(-\frac{3}{2},-\frac{1}{2}, \frac{1}{2}\right) \end{aligned} $$

About this question

Subject: Physics · Chapter: Properties of Solids and Liquids · Topic: Elasticity

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