A wire of length L is hanging from a fixed support. The length changes to L1 and L2 when masses 1 kg and 2 kg are suspended respectively from its free end. Then the value of L is equal to :
Solution
<p>$y = {{FL} \over {A\Delta L}}$</p>
<p>$\Rightarrow \Delta L = {{FL} \over {Ay}}$</p>
<p>$\Rightarrow {L_1} = L + {{(1g)L} \over {Ay}}$ ..... (i)</p>
<p>and ${L_2} = L + {{(2g)L} \over {Ay}}$ ..... (ii)</p>
<p>$\Rightarrow L = 2{L_1} - {L_2}$</p>
About this question
Subject: Physics · Chapter: Properties of Solids and Liquids · Topic: Elasticity
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