A bicycle tyre is filled with air having pressure of $270 ~\mathrm{kPa}$ at $27^{\circ} \mathrm{C}$. The approximate pressure of the air in the tyre when the temperature increases to $36^{\circ} \mathrm{C}$ is
Solution
$\mathrm{P}_{\text {in }}=270 \mathrm{kPa}, \mathrm{T}_{\text {in }}=27^{\circ} \mathrm{C}$
<br/><br/>
$=300 \mathrm{~K}$
<br/><br/>
$\mathrm{T}_{\text {final }}=36^{\circ} \mathrm{C}=309 \mathrm{~K}$
<br/><br/>
Hence we can consider process to be isochoric volume constant
<br/><br/>
$\therefore P \propto T$
<br/><br/>
$$
\frac{P_{\text {in }}}{P_{f}}=\frac{T_{\text {in }}}{T_{f}} \Rightarrow P_{f}=278 ~\mathrm{kPa}
$$
About this question
Subject: Physics · Chapter: Properties of Solids and Liquids · Topic: Elasticity
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