"In Millikan's oil drop experiment, what is viscous force acting on an uncharged drop of radius 2.0 $\times$ 10$-$5 m and density 1.2 $\times$ 103 kgm$-$3 ? Take viscosity of liquid = 1.8 $\times$ 10$-$5 Nsm$-$2. (Neglect buoyancy due to air)."

Question

Accepted Answer

"Viscous force = Weight

$= \rho \times \left( {{4 \over 3}\pi {r^3}} \right)g$

= 3.9 $\times$ 10^$-$10"

In Millikan's oil drop experiment, what is viscous force acting on an uncharged drop of radius 2.0 $\times$ 10^$-$5 m and density 1.2 $\times$ 10³ kgm^$-$3 ? Take viscosity of liquid = 1.8 $\times$ 10^$-$5 Nsm^$-$2. (Neglect buoyancy due to air).

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In Millikan's oil drop experiment, what is viscous force acting on an uncharged drop of radius 2.0 $\times$ 10$-$5 m and density 1.2 $\times$ 103 kgm$-$3 ? Take viscosity of liquid = 1.8 $\times$ 10$-$5 Nsm$-$2. (Neglect buoyancy due to air).

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In Millikan's oil drop experiment, what is viscous force acting on an uncharged drop of radius 2.0 $\times$ 10^$-$5 m and density 1.2 $\times$ 10³ kgm^$-$3 ? Take viscosity of liquid = 1.8 $\times$ 10^$-$5 Nsm^$-$2. (Neglect buoyancy due to air).