Medium MCQ +4 / -1 PYQ · JEE Mains 2021

The value of tension in a long thin metal wire has been changed from T1 to T2. The lengths of the metal wire at two different values of tension T1 and T2 are l1 and l2 respectively. The actual length of the metal wire is :

  1. A ${{{l_1} + {l_2}} \over 2}$
  2. B $\sqrt {{T_1}{T_2}{l_1}{l_2}}$
  3. C ${{{T_1}{l_2} - {T_2}{l_1}} \over {{T_1} - {T_2}}}$ Correct answer
  4. D ${{{T_1}{l_1} - {T_2}{l_2}} \over {{T_1} - {T_2}}}$

Solution

Suppose, I<sub>0</sub> be the actual length of metal wire and Y be its Young's modulus.<br/><br/>From Hooke's law,<br/><br/>$Y = {{T{I_0}} \over {A\Delta I}}$<br/><br/>where, $\Delta I = I - {I_0}$<br/><br/>$\Rightarrow Y = {{T{I_0}} \over {A(I - {I_0})}}$ or $I - I = {{T{I_0}} \over {AY}}$<br/><br/>$\therefore$ $${{{I_1} - {I_0}} \over {{I_2} - {I_0}}} = {{{T_1}{I_0}} \over {AY}} \times {{AY} \over {{T_2}{I_0}}} = {{{T_1}} \over {{T_2}}} $$<br/><br/>$\Rightarrow {I_1}{T_2} - {I_0}{T_2} = {I_2}{T_1} - {I_0}{T_1}$<br/><br/>$$ \Rightarrow {I_0} = {{{I_1}{T_2} - {I_2}{T_1}} \over {{T_2} - {T_1}}} = {{{T_1}{I_2} - {T_2}{I_1}} \over {({T_1} - {T_2})}}$$

About this question

Subject: Physics · Chapter: Properties of Solids and Liquids · Topic: Elasticity

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