When a rubber ball is taken to a depth of __________m in deep sea, its volume decreases by 0.5%.
(The bulk modulus of rubber = 9.8 $\times$ 108 Nm$-$2, Density of sea water = 103 kgm$-$3, g = 9.8 m/s2)
Answer (integer)
500
Solution
$$B = - {{\Delta P} \over {\left( {{{\Delta V} \over V}} \right)}} = - {{\rho gh} \over {\left( {{{\Delta V} \over V}} \right)}}$$<br><br>$- {{B{{\Delta V} \over V}} \over {\rho g}} = h$<br><br>${{9.8 \times {{10}^8} \times 0.5} \over {100 \times {{10}^3} \times 9.8}} = h$<br><br>h = 500
About this question
Subject: Physics · Chapter: Properties of Solids and Liquids · Topic: Elasticity
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