Two soap bubbles of radius 2 cm and 4 cm , respectively, are in contact with each other. The radius of curvature of the common surface, in cm , is _________.
Answer (integer)
4
Solution
<p>To find the radius of curvature of the common surface between two soap bubbles, we use the formula:</p>
<p>$ r = \left| \frac{{r_1 \cdot r_2}}{{r_1 - r_2}} \right| $</p>
<p>Given that $ r_1 = 2 \, \text{cm} $ and $ r_2 = 4 \, \text{cm} $, we substitute these values into the formula:</p>
<p>$ r = \left| \frac{2 \cdot 4}{2 - 4} \right| = \left| \frac{8}{-2} \right| = 4 \, \text{cm} $</p>
<p>Thus, the radius of curvature of the common surface is $ 4 \, \text{cm} $.</p>
About this question
Subject: Physics · Chapter: Properties of Solids and Liquids · Topic: Elasticity
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